| 87624 | The lab analyst performs a test to determine the presence of human papillomavirus, or HPV. The provider uses nucleic acid detection for high–risk types and produces a pooled result. | 19 | 30 | 910 | $40 | $638.8K |
| 87536 | A lab tests a patient’s specimen to measure the amount of HIV–1 present. This may be referred to as viral load. | 32 | 40 | 250 | $80 | $140.8K |
| 87426 | The lab analyst performs an immunoassay to qualitatively or semiquantitatively evaluate the patient blood specimen for antigens of severe acute respiratory syndrome coronavirus such as SARS–CoV–2,… | 397 | 650 | 1,260 | $40 | $93.7K |
| 87490 | The lab analyst performs a test for Chlamydia trachomatis using direct nucleic acid probe technique. Chlamydia trachomatis causes a common sexually transmitted disease and certain eye infections. | 19 | 70 | 150 | $20 | $71.9K |
| 84443 | The lab analyst performs a test to measure the amount of thyroid–stimulating hormone (TSH), a hormone produced in the pituitary gland that helps regulate thyroid function. The typical specimen is the… | 97 | 770 | 2,520 | $20 | $65.5K |
| G2023 | Specimen collection for severe acute respiratory syndrome coronavirus 2 (sars-cov-2) (coronavirus disease [covid-19]), any specimen source | 226 | 590 | 1,440 | $20 | $65.4K |
| 87635 | Using an amplified nucleic acid probe technique, the lab analyst performs the necessary steps to identify the nucleic acids from the severe acute respiratory syndrome coronavirus 2 (SARS–COV–2) virus… | 110 | 370 | 370 | $50 | $63.3K |
| 87590 | The lab analyst performs a test for Neisseria gonorrhoeae, a bacteria, using direct nucleic acid probe technique. | 23 | 80 | 150 | $20 | $59.4K |
| 80061 | The lab analyst performs a lipid panel test in which he measures the blood level of cholesterol and fats called triglycerides in the blood. | 92 | 810 | 2,350 | $10 | $52.7K |
| 87591 | The lab analyst performs a lab test for Neisseria gonorrhoeae, also called GC, using amplified nucleic acid probe technique. | 248 | 290 | 170 | $30 | $43.8K |