| 87798 | The lab analyst performs a test for an infectious agent not specified in another code using an amplified nucleic acid probe technique. Use this code if you know the laboratory technique is amplified… | 2,130 | $30 | $72.4K |
| 87801 | The lab analyst performs a test for multiple infectious agents using amplified nucleic acid probe technique. | 500 | $70 | $34.2K |
| 99214 | The provider sees an established patient for an office visit or other outpatient visit involving evaluation and management. The visit involves a moderate level of medical decision making, and/or the… | 310 | $90 | $26.7K |
| 99213 | The provider sees an established patient for an office visit or other outpatient visit involving evaluation and management. The visit involves a low level of medical decision making, and/or the… | 410 | $60 | $23K |
| 87481 | The lab analyst performs a test for Candida species using amplified nucleic acid probe technique. | 660 | $30 | $22.3K |
| 52648 | Transurethral resection of the prostate is performed in cases of BPH (benign prostate hyperplasia) which commonly occurs in middle–aged and elderly men, often causing lower urinary symptoms, with… | 20 | $500 | $9.9K |
| 52356 | The provider performs a cystourethroscopy, the inspection of the interior of the bladder, the urethra, prostatic urethra, and ureteric openings using a cystoscope passed through the urethra and into… | 30 | $320 | $8.9K |
| 99204 | The provider sees a new patient for an office visit or other outpatient visit involving evaluation and management. The visit involves a moderate level of medical decision making, and/or the provider… | 60 | $110 | $6.3K |
| 87500 | The lab analyst performs a test for vancomycin resistance in an infectious organism’s nucleic acid using amplified probe technique. VRE, vancomycin resistant enterococcus, is the most common organism… | 170 | $30 | $5.7K |
| 87640 | The lab analyst performs the technical lab test to look for Staphylococcus aureus nucleic acid using an amplified probe technique. | 170 | $30 | $5.7K |