| 87150 | The lab analyst performs an analysis using amplified DNA or RNA probe technique on a previously isolated and identified organism to categorize the organism more specifically, such as to the taxonomic… | 11,730 | $30 | $398.6K |
| 87801 | The lab analyst performs a test for multiple infectious agents using amplified nucleic acid probe technique. | 2,930 | $70 | $202.4K |
| 99214 | The provider sees an established patient for an office visit or other outpatient visit involving evaluation and management. The visit involves a moderate level of medical decision making, and/or the… | 1,780 | $90 | $156.3K |
| 87481 | The lab analyst performs a test for Candida species using amplified nucleic acid probe technique. | 1,960 | $30 | $66.5K |
| 87798 | The lab analyst performs a test for an infectious agent not specified in another code using an amplified nucleic acid probe technique. Use this code if you know the laboratory technique is amplified… | 1,960 | $30 | $66.5K |
| 99213 | The provider sees an established patient for an office visit or other outpatient visit involving evaluation and management. The visit involves a low level of medical decision making, and/or the… | 780 | $60 | $49.2K |
| 52000 | In this procedure, the provider performs an examination of the interior of the bladder, the urethra, and the ureteric openings by means of a cystourethroscope, a thin flexible or rigid tube with a… | 200 | $180 | $35.1K |
| 87500 | The lab analyst performs a test for vancomycin resistance in an infectious organism’s nucleic acid using amplified probe technique. VRE, vancomycin resistant enterococcus, is the most common organism… | 980 | $30 | $33.3K |
| 87651 | The lab analyst performs a test for the bacteria Streptococcus, group A, using amplified nucleic acid probe technique. Strep A commonly causes acute pharyngitis, or strep throat. | 980 | $30 | $33.3K |
| 87640 | The lab analyst performs the technical lab test to look for Staphylococcus aureus nucleic acid using an amplified probe technique. | 980 | $30 | $33.2K |